TypeScript 怎样动态获取 import * as 导入的内容？

This topic created in 1686 days ago, the information mentioned may be changed or developed.

代码如下：

// file1.ts
export * from "aaa";
export * from "bbb";
export * from "ccc";
export const a = 1;
export const b = 2;

// file2.ts
import * as balala from "./file1.ts";
Object.getOwnPropertyNames(balala)
    .forEach((key) => {
    		const module = balala[key];
    });

在使用balala[key]获取模块时爆红了，提示如下；搜索半天无果，请教下这种情况该怎么解决呢？

Element implicitly has an 'any' type because expression of type 'string' can't be used to index type 'typeof import("/Users/xxxx/xxx/file1.ts")

4 replies • 2021-10-25 20:28:26 +08:00

Danswerme

Oct 25, 2021

暂时用类型断言解决了，但是总感觉怪怪的，v 友们如果有更好的解决方案麻烦回复下。

```
const balalaAlias = <any>balala;

const module = balalaAlias[key];
```

anjianshi

Oct 25, 2021

```typescript

// 先把 balala 从 TypeScript namespace 转换成普通对象，接下来就可以当普通对象来处理了
const moduleObject = { ...balala }

Object.getOwnPropertyNames(moduleObject).forEach(key => {
// 把字符串 key 标识成 moduleObject 的带类型信息的 key
const o = obj[key as (keyof (typeof moduleObject))]
console.log(o)
})

```

lzgshsj

Oct 25, 2021

const module = balala[key as keyof typeof balala]
具体可以去了解一下 keyof 和 typeof 的用法

Danswerme

Oct 25, 2021

@anjianshi
@lzgshsj
感谢，学习到用法了。