web.py 如何设置模板中链接从新窗口打开？

report.py:

import web
import model

render = web.template.render('templates', base='base')

urls = (
'/', 'index',
'/report/(.*)', 'report'
)

class index:
def GET(self):
scanlog = model.get_scanlog()
return render.scanlog(scanlog)

class report:
def POST(self, id):
report = model.get_report(id)
return render.report(report)

if __name__ == "__main__":
app = web.application(urls, globals())
app.run()
-----------------------------------------------------------------
index.html模板：
$def with (scanlog)
<table>
$for x in scanlog
<tr>
<form action="/report/$x.ScanID" method="post" tartget="_blank">
<input type="submit" value="Report" />
</form>
</tr>
</table>