var value = '1,2,3,4,5,6,7,8,9'
输出[2, 5, 8]
输出索引匹配 i%3===1 的整形数组
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This topic created in 2571 days ago, the information mentioned may be changed or developed.
2 replies • 2019-06-12 10:54:33 +08:00
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1
cyd May 24, 2019
value.split(",").filter((i,j)=>j%3===1)
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2
bdbd001 Jun 12, 2019
value.split(",").map((i)=>i*1).filter((i)=>(i%3===2))
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