Linux BASH 文本处理求助 - V2EX

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This topic created in 2758 days ago, the information mentioned may be changed or developed.

有以下源文件 a.txt：

# This is a file
// Comments
somechars
somechars,somechar
somechars,somechars,somechars

需求：
在有且只有一个逗号的情况下，在行末插入指定字符串。在有 2 个逗号的情况下，在第二个逗号前插入指定字符串。

输出效果 output.txt:

# This is a file
// Comments
somechars
somechars,somechar,STRTOBEINSERT
somechars,somechars,STRTOBEINSERT,somechars

求教如何实现这个效果，使用 sed/awk 都可以，多谢🙏

6 replies • 2018-11-17 19:56:58 +08:00

1

ifaii

Nov 17, 2018

x='|STRTOBEINSERT|'
perl -pe "s/(.*?)(,)(.*?)(,)(.*$)/\1\2\3$x\4\5/g || s/(.*?)(,)(.*$)/\1$x\2\3/g" filename

我又复习了一次 perl 的用法

2

ifaii

Nov 17, 2018

1

看错题目了，稍微改一下参数位置即可

x='|STRTOBEINSERT|'

perl -pe "s/(.*?)(,)(.*?)(,)(.*$)/\1\2\3$x\4\5/g || s/(.*?)(,)(.*$)/\1\2\3$x/g" filename

3

l76862157

Nov 17, 2018

1

awk -F',' '{if(NF==2){print $0", STRTOBEINSERT"} else if(NF==3){print $1","$2", STRTOBEINSERT,"$3}else{print}}'

4

DiamondbacK

Nov 17, 2018

1

sed 's/[^,]*,[^,]*/&,STRTOBEINSERT/'
gawk 'NF>1 {$2=$2 ",STRTOBEINSERT"} {print}' FS=, OFS=,

5

uuspider

Nov 17, 2018

2

sed 's/\([^,]*,[^,]*\)\(.*\)/\1,STRTOBEINSERT\2/'

6

maxduke

OP

Nov 17, 2018

以上各位回复都感谢啦，🙏

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