pyhton 怎么求某点的导数值 - V2EX

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This topic created in 2854 days ago, the information mentioned may be changed or developed.

from sympy import *
x=Symbol('x')
y=x**2
dx=diff(y,x)
上面这段程序求出了 y 关于 x 的导数：dx=2*x
如何求 x=2 时，导数的值 dx=2*2=4 呢？
这个要怎么代入呢？我的意思如何通过程序做。

1 replies

1

metaquant

Aug 13, 2018

from sympy import *
dx=2*x
u = lambdify(x,dx)
print(u(2))

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