grep -Po 使用问题

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{
"result":[
{
"id":"652bcd",
"type":"1",
"name":"san",
"content":"santest",
"created_on":"2016-03-22T01:41:55",
"meta":{
"auto_added":false
}
}
],
"result_info":{
"count":1,
"total_count":1
},
"success":true,
"errors":[
],
"messages":[
]
}

怎么才能抓取{"id":"652bcd","type":"1","name":"san","content":"santest","created_on":"2016-03-22T01:41:55","meta":{"auto_added":false}}
这一部分内容
抓取名字我用的 grep -Po '(?<="name":")[^"]*'

name

created_on

auto_added

2016-03-22

3 replies • 2016-06-26 18:09:19 +08:00

SoloCompany

Jun 25, 2016

npm install node-select

echo '{
"result":[
{
"id":"652bcd",
"type":"1",
"name":"san",
"content":"santest",
"created_on":"2016-03-22T01:41:55",
"meta":{
"auto_added":false
}
}
],
"result_info":{
"count":1,
"total_count":1
},
"success":true,
"errors":[
],
"messages":[
]
}
' | ./node_modules/.bin/json-select 'result.*'
[
{
"id": "652bcd",
"type": "1",
"name": "san",
"content": "santest",
"created_on": "2016-03-22T01:41:55",
"meta": {
"auto_added": false
}
}]

ericFork

Jun 26, 2016

用 jq 或者 pip 到 python -c

ericFork

Jun 26, 2016

@ericFork *pipe